This experiment employs a cart sliding on a (frictionless? nope...) track.
A force is applied to the cart through a DC motor. The input to the system
is a voltage, V(t), applied to the motor, and the output of the system is
the displacement of the cart, x(t). You will place a unity-gain feedback
loop around the plant for position control.
Using the transfer function relating x(t) / V(t), you will investigate
the response of the system using the
root-locus technique, and also investigate the
use of a PI compensator for reducing
steady-state error.
X(s) G(s) = ------- V(s)The cart was modeled as a simple mass sliding without friction (Of course, this assumption of a frictionless surface is far from true. As you do the experiment, keep this fact in mind!).
(1) Place a unity-gain feedback loop around the experimental plant, and implement a simple proportional gain controller, Kp. Note that an extra gain of 8 is required in the loop to account for the transfer function between output voltage from the potentiometer to displacement in [cm]. (2) Choose a square wave input, with frequency w=0.2Hz and amplitute A=5cm. (3) Run the system for Kp = 0.1, 0.3, 0.5, 0.7, 1.0, 3.0, 5.0. SAVE THE DATA FROM EACH RUN UNDER FILES A3_01.m, A3_03.m, ..., A3_50.m
Assignment:
A1. Use Matlab to draw the theoretical root locus for the system, and find the value of the total gain, Kp*Kplant, when the system is critically damped ,i.e. when the poles of T(s) meet on the real axis. A2. Add your experimental points to the RL plot, and label the value of Kp at each point. To calculate the colsed-loop pole locations for each Kp, use MatLab to measure the damped frequency (wd) or the exponential frequency (sigma) from each time-domain plot. A3. Use the plot of your experimental data from A2 to estimate the actual value of Kp when the system is critically damped. A4. Use the results of A1 and A2 to derive the value of plant gain, Kplant. A5. During the experiment, you may have noticed that the steady-state error was not approaching zero for small values of Kp even though the system type = 1. Based on the physical nature of the system, can you explain why this may be so?
(B) PI Control:
In theory, the plant is a type 1 system and should thus yield constant steady-state error for a ramp input: R(s)=A/s^2 <---> r(t)=At. In this section you will implement a PI controller to eliminate the steady-state error for a ramp input.
The implementation of a cascade PI controller looks like:
To explore the behavior of such a controller, do the following:
(1) Use ramp input (sawtooth), and set A=10cm, w=0.2Hz (2) First, run the system without a PI controller to observe the steady-state error. Collect data for proportional gains of Kp=0.1, 0.5, 1.0. SAVE THE DATA FROM EACH RUN UNDER FILES NAMED B2_01.m, B2_05.m, B2_10.m (3) Implement a PI controller: s + Zpi Gc(s) = ------ * Kp = Kp + Ki/s (where Ki = Zpi*Kp) s Set Kp=0.5, and collect data for Ki=0.1, 0.5, 1.0. Observe the S.S. errors. Note whether Ess=0 for each case, and how the transient response is affected. SAVE THE DATA FROM EACH RUN UNDER FILES NAMED B3_01.m, B3_05.m, B3_10.m
Assignment:
B1. Derive the expression for Ess without the PI controller. B2. Using the value of Kplant found in Assignment A3, and the values of K used in part B(2), compare the theoretical and experimental values of Ess. If your values do not agree, try to explain why this may be so. B3. Derive the expression for Ess with the PI controller, and show that Ess=0 for a ramp input. B4. Describe your observations when the PI zero is moved futher into the LHP in terms of Ess and transient response. Can you explain what is happening?