function P=findpeaks(x,y,SlopeThreshold,AmpThreshold,smoothwidth,peakgroup) % function P=findpeaks(x,y,SlopeThreshold,AmpThreshold,smoothwidth,peakgroup) % Function to locate the positive peaks in a noisy x-y data % set. Detects peaks by looking for downward zero-crossings % in the first derivative that exceed SlopeThreshold. % Returns list (P) containing peak number and % position, height, and width of each peak. SlopeThreshold, % AmpThreshold, and smoothwidth control sensitivity % Higher values will neglect smaller features. Peakgroup % is the number of points around the "top part" of the peak. % T. C. O'Haver, 1995. Version 2 Last revised Oct 27, 2006 smoothwidth=round(smoothwidth); peakgroup=round(peakgroup); d=fastsmooth(deriv(y),smoothwidth); n=round(peakgroup/2+1); P=[0 0 0 0]; vectorlength=length(y); peak=1; AmpTest=AmpThreshold; for j=smoothwidth:length(y)-smoothwidth, if sign(d(j)) > sign (d(j+1)), % Detects zero-crossing if d(j)-d(j+1) > SlopeThreshold*y(j), % if slope of derivative is larger than SlopeThreshold if y(j) > AmpTest, % if height of peak is larger than AmpThreshold for k=1:peakgroup, % Create sub-group of points near peak groupindex=j+k-n+1; if groupindex<1, groupindex=1;end if groupindex>vectorlength, groupindex=vectorlength;end xx(k)=x(groupindex);yy(k)=y(groupindex); end [coef,S,MU]=polyfit(xx,log(abs(yy)),2); % Fit parabola to log10 of sub-group with centering and scaling c1=coef(3);c2=coef(2);c3=coef(1); PeakX=-((MU(2).*c2/(2*c3))-MU(1)); % Compute peak position and height of fitted parabola PeakY=exp(c1-c3*(c2/(2*c3))^2); MeasuredWidth=norm(MU(2).*2.35703/(sqrt(2)*sqrt(-1*c3))); % if the peak is too narrow for least-squares technique to work % well, just use the max value of y in the sub-group of points near peak. if peakgroup<7, PeakY=max(yy); pindex=val2ind(yy,PeakY); PeakX=xx(pindex(1)); end % Construct matrix P. One row for each peak % detected, containing the peak number, peak % position (x-value) and peak height (y-value). P(peak,:) = [round(peak) PeakX PeakY MeasuredWidth]; peak=peak+1; end end end end function [index,closestval]=val2ind(x,val) % Returns the index and the value of the element of vector x that is closest to val % If more than one element is equally close, returns vectors of indicies and values % Tom O'Haver (toh@umd.edu) October 2006 % Examples: If x=[1 2 4 3 5 9 6 4 5 3 1], then val2ind(x,6)=7 and val2ind(x,5.1)=[5 9] % [indices values]=val2ind(x,3.3) returns indices = [4 10] and values = [3 3] dif=abs(x-val); index=find((dif-min(dif))==0); closestval=x(index);